A very simple Win98/Puppy dual boot with grub

[arslan]

Hi Puppy people,

I thought I'd share this with you:

For a while I had been using HD installed Puppy 2.13 with WakePup2
diskette as the booting method. However, I desired a more elegant solution.
So I downloaded Grub for DOS (http://sarovar.org/download.php/1138/gr ... -0.4.2.zip),
put grub.exe in C:\, added the following line to autoexec.bat:

c:\grub.exe

and put the following menu.lst file to C:\

=========================================
# Boot automatically after a minute.
timeout 60

# By default, boot this entry.
default 0

title Puppy
rootnoverify (hd0,0)
kernel (hd0,0)/vmlinuz root=/dev/ram PFILE=pup_213.sfs
initrd (hd0,0)/initrd.gz
boot

title Win98
savedefault --wait=2
quit
=========================================
(Since I already had Puppy installed to HD, in C:\ I already had these:
initrd.gz, pup_213.sfs, pup_save.2fs, pupswap.swp, vmlinuz and zdrv_213.sfs)

That's all, works nicely.

[Sit Heel Speak]

Interesting. I'd always thought you had to specify a device number on the ram device, i.e.

root=/dev/ram0

in the kernel line.